Maura Murray

Well said Mr. Benjamin Franklyne. I thought from the start that Pomkik was Alden Olson and now we have confirmation. I feel sorry for him. That feeling of hope you felt is what makes you human, my friend. I felt it too and it's nothing to be ashamed of. It's what separates us from the Alden Olson's of the world.

Doesn't actually harm people, it protects them.

Want more?

The BW ski ticket is real. No Question.

I do not know for certain that FrmLE and Cyberlaw are the same person but after reading over hundreds of posts it is a very reasonable assumption. I would bet money this though.

A one point in time Alden stated online that He had a red truck. I am looking for that now.

Alden Howes Olson wants to be famous be it for whatever reason.

He has to be unstable to put himself in the middle of this situation.

Seems that Jim Vittum has put himself right in the middle of the Stacey Burns murder case right here in the Lakes region NH. He did this from day one and he is the biggest SUSPECT.

John

http://www.dukesouthard.com/
**********

"Gilbert said the police aren’t about to relegate the case to the unsolved file, and Jim Vittum is the reason.

Vittum has offered alibis for everything the department has thrown at him, even laying out a detailed scenario in which he contends Ed Burns could have driven from Boston, killed Stacey, and driven back.

But Gilbert isn’t buying it and says the department “is in constant communication” with Vittum by email. He also confirmed that Vittum's blood was found under Stacey’s fingernails.

“What’s missing is the person doing it coming to terms with it,” he said of the case.

Asked if that was a reference to Vittum, Gilbert replied,“Yep. He’s not that smart. It’ll happen, it’ll come.”

Vittum didn’t respond to several phone calls last week from the Green Valley News.

•••

http://m.gvnews.com/sahuarita_sun/news/small-...
**********

Put Yourself right in the middle of the investigation and keep Yourself in the loop. Not Smart.....but not Stupid...!

John

Det Columbo wrote:

I do not know for certain that FrmLE and Cyberlaw are the same person but after reading over hundreds of posts it is a very reasonable assumption..
John

From what I remember, cyberlaw is a female from Canada.

A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for constant acceleration, the relations a =( V - v )/ t and x =½( V + v ) t. Here v is the particle's speed at t = 0 and V is its speed at time t. The the work done is W = F x = m a x = m (( V - v )/ t )(½( V + v )) t =½ m V²-½ m v². We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K =½ m v². We may then state the above equation in this way: The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.

oo00oo wrote:

<quoted text>
From what I remember, cyberlaw is a female from Canada.

I have no idea who this person is...but enough of this shit.

A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for constant acceleration, the relations a =( V - v )/ t and x =½( V + v ) t. Here v is k done is W = F x = m a x = m (( V - v )/ t )(½( V + v )) t =½ m V²-½ m v². We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K =½ m v². We may then state the above equation in this way: The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.

oo00oo wrote:

<quoted text>
From what I remember, cyberlaw is a female from Canada.

What! Another one of the detectives conclusions are total bullshit? Surely you jest?

I don't know.... He has such a stellar track record I'm inclined to believe his sleuthing skills. NOT!

What is even more interesting is why he should care. I mean if he sucks as bad at this sleuthing stuff as it appears he does should he even be trying? Especially in a public forum. Add that to the fact, I don't give a shit who Cyberlaw is or Snowy or Jenkins. I CARE ABOUT THE CONTENT OF THEIR POSTS! That is all that is important to me.

Another major public embarrassment for the "detective". If I may make a suggestion. Stop spreading yourself so thin. All these other cases are a distraction that you just can't afford, intellectually. You're having enough difficulty just screwing this case up without worrying about other cases and trying to discuss them here also. Focus detective, FOCUS.

I await with baited breath further breakthroughs that you will make.

Still, no one can claim that this isn't entertaining as hell. There is nothing like watching humans chase their invisible tails.

Bill

A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for constant acceleration, the relations a =( V - v )/ t and x =½( V + v ) t. Here v is the particle's speed at t = 0 and V is its speed at time t. The the work done is W = F x = m a x = m (( V - v )/ t )(½( V + v )) t =½ m V²-½ m v². We call one-half the product of the mass hen state the above equation in this way: The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.

A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for constant acceleration, the relations a =( V - v )/ t and x =½( V + v ) t. Here v is the . We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K =½ m v². We may then state the above equation in this way: The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.

A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for constant acceleration, the relations a =( V - v )/ t and x =½( V + v ) t. x = m a x = m (( V - v )/ t )(½( V + v )) t =½ m V²-½ m v². We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K =½ m v². We may then state the above equation in this way: The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.

A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for constant acceleration, the relations a =( V - v )/ t and x =½( V += m (( V - v )/ t )(½( V + v )) t =½ m V²-½ m v². We call one-half the product of the mass of a body and the square of its speed the kinetic energy of the body. If we represent kinetic energy by the symbol K, then K =½ m v². We may then state the above equation in this way: The work done by the resultant force acting on a particle is equal to the change in the kinetic energy of the particle.

A constant force, acting on a particle of mass m, will produce a constant acceleration a. Let us choose the x-axis to be in the common direction of F and a. What is the work done by this force on the particle in causing a displacement x? We have, for

BOGANEN - byword describing the unmistakably smell from german astronauts using subtle body language in Canadian roadmovies. 

LICUHYTT(noun)- pig latin for religious businessmen attending AA-meetings. 

DÆMNINUSP - the psychiatric term for businessmen beeing attacked by seagulls.
ISAMI - description of any situation that includes self-conscious bureaucrats getting arrested for mail-fraud as a sign from God. 

NITGAMAS - a famous metaphor for selfishness based on a story about strugling web designers licking on toads in search of true love.

BOGANEN - byword describing the unmistakably smell from german astronauts using subtle body language in Canadian roadmovies. 

LICUHYTT(noun)- pig latin for religious businessmen attending AA-meetings. 

DÆMNINUSP - the psychiatric term for businessmen beeing attacked by seagulls.
ISAMI - description of any situation that includes self-conscious bureaucrats getting arrested for mail-fraud as a sign from God. 

NITGAMAS - a famous metaphor for selfishness based on a story about strugling web designers licking on toads in search of true love.

BOGANEN - byword describing the unmistakably smell from german astronauts using subtle body language in Canadian roadmovies. 

LICUHYTT(noun)- pig latin for religious businessmen attending AA-meetings. 

DÆMNINUSP - the psychiatric term for businessmen beeing attacked

NITGAMAS - a famous metaphor for selfishness based on a story about strugling web designers licking on toads in search of true love.

could it be? what is ThiS?

http://grokbase.com/t/python/patches/042ace9b...

https://mail.python.org/pipermail/patches/200...

Mara Murray ////////\\
Wed Feb 11 07:42:16 EST 2004

http://osdir.com/ml/python-patches/2004-02/ms...

Your Bullshit Goes in the Red Herrings Forum Columbo.